Base | Representation |
---|---|
bin | 10100111011001111… |
… | …00011110011110001 |
3 | 1001222221100222112120 |
4 | 22131213203303301 |
5 | 141001441442133 |
6 | 5054434344453 |
7 | 545253132153 |
oct | 123547436361 |
9 | 31887328476 |
10 | 11234327793 |
11 | 4845537827 |
12 | 221642b129 |
13 | 10a0640750 |
14 | 78806aad3 |
15 | 45b429ab3 |
hex | 29d9e3cf1 |
11234327793 has 8 divisors (see below), whose sum is σ = 16131342528. Its totient is φ = 6913432464.
The previous prime is 11234327779. The next prime is 11234327807. The reversal of 11234327793 is 39772343211.
It is an interprime number because it is at equal distance from previous prime (11234327779) and next prime (11234327807).
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 11234327793 - 28 = 11234327537 is a prime.
It is a super-4 number, since 4×112343277934 (a number of 41 digits) contains 4444 as substring.
It is not an unprimeable number, because it can be changed into a prime (11234307793) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 144029805 + ... + 144029882.
It is an arithmetic number, because the mean of its divisors is an integer number (2016417816).
Almost surely, 211234327793 is an apocalyptic number.
11234327793 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
It is an amenable number.
11234327793 is a deficient number, since it is larger than the sum of its proper divisors (4897014735).
11234327793 is a wasteful number, since it uses less digits than its factorization.
11234327793 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 288059703.
The product of its digits is 190512, while the sum is 42.
The spelling of 11234327793 in words is "eleven billion, two hundred thirty-four million, three hundred twenty-seven thousand, seven hundred ninety-three".
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