Base | Representation |
---|---|
bin | 110100010100000101… |
… | …1110101010011111111 |
3 | 101201222101210222221002 |
4 | 1220220023311103333 |
5 | 3320034343342122 |
6 | 123335415400515 |
7 | 11054654431223 |
oct | 1505013652377 |
9 | 351871728832 |
10 | 112343340287 |
11 | 4370a983382 |
12 | 1993368313b |
13 | a794b380a9 |
14 | 561a4d4783 |
15 | 2dc7bca992 |
hex | 1a282f54ff |
112343340287 has 2 divisors, whose sum is σ = 112343340288. Its totient is φ = 112343340286.
The previous prime is 112343340181. The next prime is 112343340301. The reversal of 112343340287 is 782043343211.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 112343340287 - 212 = 112343336191 is a prime.
It is a super-2 number, since 2×1123433402872 (a number of 23 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 112343340287.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (112343340887) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56171670143 + 56171670144.
It is an arithmetic number, because the mean of its divisors is an integer number (56171670144).
Almost surely, 2112343340287 is an apocalyptic number.
112343340287 is a deficient number, since it is larger than the sum of its proper divisors (1).
112343340287 is an equidigital number, since it uses as much as digits as its factorization.
112343340287 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 96768, while the sum is 38.
Adding to 112343340287 its reverse (782043343211), we get a palindrome (894386683498).
The spelling of 112343340287 in words is "one hundred twelve billion, three hundred forty-three million, three hundred forty thousand, two hundred eighty-seven".
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