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112343340301 is a prime number
BaseRepresentation
bin110100010100000101…
…1110101010100001101
3101201222101210222221121
41220220023311110031
53320034343342201
6123335415400541
711054654431243
oct1505013652415
9351871728847
10112343340301
114370a983395
1219933683151
13a794b380ba
14561a4d4793
152dc7bca9a1
hex1a282f550d

112343340301 has 2 divisors, whose sum is σ = 112343340302. Its totient is φ = 112343340300.

The previous prime is 112343340287. The next prime is 112343340349. The reversal of 112343340301 is 103043343211.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 75927251401 + 36416088900 = 275549^2 + 190830^2 .

It is a cyclic number.

It is not a de Polignac number, because 112343340301 - 223 = 112334951693 is a prime.

It is a super-2 number, since 2×1123433403012 (a number of 23 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (112343340601) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56171670150 + 56171670151.

It is an arithmetic number, because the mean of its divisors is an integer number (56171670151).

Almost surely, 2112343340301 is an apocalyptic number.

It is an amenable number.

112343340301 is a deficient number, since it is larger than the sum of its proper divisors (1).

112343340301 is an equidigital number, since it uses as much as digits as its factorization.

112343340301 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2592, while the sum is 25.

Adding to 112343340301 its reverse (103043343211), we get a palindrome (215386683512).

The spelling of 112343340301 in words is "one hundred twelve billion, three hundred forty-three million, three hundred forty thousand, three hundred one".