1123434331031 has 2 divisors, whose sum is σ = 1123434331032. Its totient is φ = 1123434331030.

The previous prime is 1123434331001. The next prime is 1123434331039. The reversal of 1123434331031 is 1301334343211.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1123434331031 - 2¹⁴ = 1123434314647 is a prime.

It is a super-2 number, since 2×1123434331031² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1123434330985 and 1123434331003.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1123434331039) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 561717165515 + 561717165516.

It is an arithmetic number, because the mean of its divisors is an integer number (561717165516).

Almost surely, 2^{1123434331031} is an apocalyptic number.

1123434331031 is a deficient number, since it is larger than the sum of its proper divisors (1).

1123434331031 is an equidigital number, since it uses as much as digits as its factorization.

1123434331031 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 7776, while the sum is 29.

Adding to 1123434331031 its reverse (1301334343211), we get a palindrome (2424768674242).

The spelling of 1123434331031 in words is "one trillion, one hundred twenty-three billion, four hundred thirty-four million, three hundred thirty-one thousand, thirty-one".