1123434331093 has 2 divisors, whose sum is σ = 1123434331094. Its totient is φ = 1123434331092.

The previous prime is 1123434331087. The next prime is 1123434331133. The reversal of 1123434331093 is 3901334343211.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1104857458884 + 18576872209 = 1051122^2 + 136297^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1123434331093 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1123474331093) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 561717165546 + 561717165547.

It is an arithmetic number, because the mean of its divisors is an integer number (561717165547).

Almost surely, 2^{1123434331093} is an apocalyptic number.

It is an amenable number.

1123434331093 is a deficient number, since it is larger than the sum of its proper divisors (1).

1123434331093 is an equidigital number, since it uses as much as digits as its factorization.

1123434331093 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 69984, while the sum is 37.

The spelling of 1123434331093 in words is "one trillion, one hundred twenty-three billion, four hundred thirty-four million, three hundred thirty-one thousand, ninety-three".