Base | Representation |
---|---|
bin | 10100111011001111… |
… | …00111101000000111 |
3 | 1001222221101202222202 |
4 | 22131213213220013 |
5 | 141001442442211 |
6 | 5054434545115 |
7 | 545253225563 |
oct | 123547475007 |
9 | 31887352882 |
10 | 11234343431 |
11 | 4845548553 |
12 | 221643819b |
13 | 10a06478bc |
14 | 7880726a3 |
15 | 45b42e53b |
hex | 29d9e7a07 |
11234343431 has 2 divisors, whose sum is σ = 11234343432. Its totient is φ = 11234343430.
The previous prime is 11234343409. The next prime is 11234343451. The reversal of 11234343431 is 13434343211.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11234343431 is a prime.
It is a super-2 number, since 2×112343434312 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 11234343394 and 11234343403.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11234343451) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5617171715 + 5617171716.
It is an arithmetic number, because the mean of its divisors is an integer number (5617171716).
Almost surely, 211234343431 is an apocalyptic number.
11234343431 is a deficient number, since it is larger than the sum of its proper divisors (1).
11234343431 is an equidigital number, since it uses as much as digits as its factorization.
11234343431 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 10368, while the sum is 29.
Adding to 11234343431 its reverse (13434343211), we get a palindrome (24668686642).
The spelling of 11234343431 in words is "eleven billion, two hundred thirty-four million, three hundred forty-three thousand, four hundred thirty-one".
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