Base | Representation |
---|---|
bin | 100001011110110… |
… | …0111100110100011 |
3 | 2220021222010122112 |
4 | 1002331213212203 |
5 | 4300100334001 |
6 | 303251225535 |
7 | 36561106151 |
oct | 10275474643 |
9 | 2807863575 |
10 | 1123449251 |
11 | 527181061 |
12 | 2742a82ab |
13 | 14b9a1092 |
14 | a92c43d1 |
15 | 68968cbb |
hex | 42f679a3 |
1123449251 has 2 divisors, whose sum is σ = 1123449252. Its totient is φ = 1123449250.
The previous prime is 1123449209. The next prime is 1123449253. The reversal of 1123449251 is 1529443211.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1123449251 is a prime.
It is a super-2 number, since 2×11234492512 = 2524276439144922002, which contains 22 as substring.
Together with 1123449253, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (1123449253) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 561724625 + 561724626.
It is an arithmetic number, because the mean of its divisors is an integer number (561724626).
Almost surely, 21123449251 is an apocalyptic number.
1123449251 is a deficient number, since it is larger than the sum of its proper divisors (1).
1123449251 is an equidigital number, since it uses as much as digits as its factorization.
1123449251 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 8640, while the sum is 32.
The square root of 1123449251 is about 33517.8944893619. The cubic root of 1123449251 is about 1039.5638120908.
The spelling of 1123449251 in words is "one billion, one hundred twenty-three million, four hundred forty-nine thousand, two hundred fifty-one".
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