Base | Representation |
---|---|
bin | 1010001101111011111101… |
… | …1000100001010010111111 |
3 | 1110210000100010112020221121 |
4 | 2203132333120201102333 |
5 | 2433031324342331020 |
6 | 35521025311411411 |
7 | 2236445426253562 |
oct | 243367730412277 |
9 | 43700303466847 |
10 | 11234550355135 |
11 | 3641600878318 |
12 | 13153b8223b67 |
13 | 63654b762a43 |
14 | 2aba801584d9 |
15 | 147382e90baa |
hex | a37bf6214bf |
11234550355135 has 8 divisors (see below), whose sum is σ = 13481497351296. Its totient is φ = 8987615667360.
The previous prime is 11234550355129. The next prime is 11234550355187. The reversal of 11234550355135 is 53155305543211.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 11234550355135 - 229 = 11234013484223 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 11234550355091 and 11234550355100.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 933244 + ... + 4831153.
It is an arithmetic number, because the mean of its divisors is an integer number (1685187168912).
Almost surely, 211234550355135 is an apocalyptic number.
11234550355135 is a deficient number, since it is larger than the sum of its proper divisors (2246946996161).
11234550355135 is an equidigital number, since it uses as much as digits as its factorization.
11234550355135 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6154193.
The product of its (nonzero) digits is 675000, while the sum is 43.
Adding to 11234550355135 its reverse (53155305543211), we get a palindrome (64389855898346).
The spelling of 11234550355135 in words is "eleven trillion, two hundred thirty-four billion, five hundred fifty million, three hundred fifty-five thousand, one hundred thirty-five".
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