Base | Representation |
---|---|
bin | 1010001101111101001101… |
… | …1011100010001010011001 |
3 | 1110210001012120101210212110 |
4 | 2203133103123202022121 |
5 | 2433033021443030213 |
6 | 35521122524302533 |
7 | 2236456652123211 |
oct | 243372333421231 |
9 | 43701176353773 |
10 | 11234886689433 |
11 | 3641763709250 |
12 | 13154909a1a49 |
13 | 6365a3342a14 |
14 | 2abab2aa9241 |
15 | 1473a277a5c3 |
hex | a37d36e2299 |
11234886689433 has 8 divisors (see below), whose sum is σ = 16341653366496. Its totient is φ = 6809022236000.
The previous prime is 11234886689431. The next prime is 11234886689479. The reversal of 11234886689433 is 33498668843211.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 11234886689433 - 21 = 11234886689431 is a prime.
It is a super-2 number, since 2×112348866894332 (a number of 27 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (11234886689431) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 170225555868 + ... + 170225555933.
It is an arithmetic number, because the mean of its divisors is an integer number (2042706670812).
Almost surely, 211234886689433 is an apocalyptic number.
It is an amenable number.
11234886689433 is a deficient number, since it is larger than the sum of its proper divisors (5106766677063).
11234886689433 is a wasteful number, since it uses less digits than its factorization.
11234886689433 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 340451111815.
The product of its digits is 143327232, while the sum is 66.
The spelling of 11234886689433 in words is "eleven trillion, two hundred thirty-four billion, eight hundred eighty-six million, six hundred eighty-nine thousand, four hundred thirty-three".
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