Base | Representation |
---|---|
bin | 1010001110010000011011… |
… | …0001110111111100110011 |
3 | 1110210112111221012012120020 |
4 | 2203210012301313330303 |
5 | 2433124102021314110 |
6 | 35523334325214523 |
7 | 2240031514252260 |
oct | 243440661677463 |
9 | 43715457165506 |
10 | 11240043151155 |
11 | 364396a371265 |
12 | 131648b861443 |
13 | 636c157236c0 |
14 | 2ac041858267 |
15 | 1475a52dad70 |
hex | a3906c77f33 |
11240043151155 has 32 divisors (see below), whose sum is σ = 22134238823424. Its totient is φ = 4743051175296.
The previous prime is 11240043151151. The next prime is 11240043151157. The reversal of 11240043151155 is 55115134004211.
It is not a de Polignac number, because 11240043151155 - 22 = 11240043151151 is a prime.
It is not an unprimeable number, because it can be changed into a prime (11240043151151) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 4117230559 + ... + 4117233288.
It is an arithmetic number, because the mean of its divisors is an integer number (691694963232).
Almost surely, 211240043151155 is an apocalyptic number.
11240043151155 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
11240043151155 is a deficient number, since it is larger than the sum of its proper divisors (10894195672269).
11240043151155 is a wasteful number, since it uses less digits than its factorization.
11240043151155 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 8234463875.
The product of its (nonzero) digits is 12000, while the sum is 33.
Adding to 11240043151155 its reverse (55115134004211), we get a palindrome (66355177155366).
The spelling of 11240043151155 in words is "eleven trillion, two hundred forty billion, forty-three million, one hundred fifty-one thousand, one hundred fifty-five".
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