1124022000131 has 2 divisors, whose sum is σ = 1124022000132. Its totient is φ = 1124022000130.

The previous prime is 1124021999959. The next prime is 1124022000133. The reversal of 1124022000131 is 1310002204211.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1124022000131 is a prime.

It is a super-2 number, since 2×1124022000131² (a number of 25 digits) contains 22 as substring.

Together with 1124022000133, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (1124022000133) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 562011000065 + 562011000066.

It is an arithmetic number, because the mean of its divisors is an integer number (562011000066).

Almost surely, 2^{1124022000131} is an apocalyptic number.

1124022000131 is a deficient number, since it is larger than the sum of its proper divisors (1).

1124022000131 is an equidigital number, since it uses as much as digits as its factorization.

1124022000131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 96, while the sum is 17.

Adding to 1124022000131 its reverse (1310002204211), we get a palindrome (2434024204342).

The spelling of 1124022000131 in words is "one trillion, one hundred twenty-four billion, twenty-two million, one hundred thirty-one", and thus it is an aban number.