Base | Representation |
---|---|
bin | 10100111100000101… |
… | …01111001001010011 |
3 | 1002000102202221021100 |
4 | 22132002233021103 |
5 | 141010302431430 |
6 | 5055251155443 |
7 | 545400523605 |
oct | 123602571123 |
9 | 32012687240 |
10 | 11241452115 |
11 | 48495633a3 |
12 | 22188a5b83 |
13 | 10a1c6641a |
14 | 788da3175 |
15 | 45bd85960 |
hex | 29e0af253 |
11241452115 has 24 divisors (see below), whose sum is σ = 19627422048. Its totient is φ = 5951675520.
The previous prime is 11241452099. The next prime is 11241452129. The reversal of 11241452115 is 51125414211.
11241452115 is a `hidden beast` number, since 1 + 124 + 1 + 4 + 521 + 15 = 666.
11241452115 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 11241452115 - 24 = 11241452099 is a prime.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 905551 + ... + 917880.
It is an arithmetic number, because the mean of its divisors is an integer number (817809252).
Almost surely, 211241452115 is an apocalyptic number.
11241452115 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
11241452115 is a deficient number, since it is larger than the sum of its proper divisors (8385969933).
11241452115 is a wasteful number, since it uses less digits than its factorization.
11241452115 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1823579 (or 1823576 counting only the distinct ones).
The product of its digits is 1600, while the sum is 27.
Adding to 11241452115 its reverse (51125414211), we get a palindrome (62366866326).
The spelling of 11241452115 in words is "eleven billion, two hundred forty-one million, four hundred fifty-two thousand, one hundred fifteen".
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