Base | Representation |
---|---|
bin | 10000010111000010000… |
… | …011101100110010000111 |
3 | 10222110212101001211121101 |
4 | 100113002003230302013 |
5 | 121404422001322043 |
6 | 2220245244200531 |
7 | 144136525101235 |
oct | 20270203546207 |
9 | 3873771054541 |
10 | 1124242214023 |
11 | 3a387446a215 |
12 | 161a76539147 |
13 | 8202831c106 |
14 | 3c5b0d53955 |
15 | 1e39dd8924d |
hex | 105c20ecc87 |
1124242214023 has 2 divisors, whose sum is σ = 1124242214024. Its totient is φ = 1124242214022.
The previous prime is 1124242214009. The next prime is 1124242214057. The reversal of 1124242214023 is 3204122424211.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1124242214023 - 213 = 1124242205831 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1124242213982 and 1124242214000.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1124242214323) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 562121107011 + 562121107012.
It is an arithmetic number, because the mean of its divisors is an integer number (562121107012).
Almost surely, 21124242214023 is an apocalyptic number.
1124242214023 is a deficient number, since it is larger than the sum of its proper divisors (1).
1124242214023 is an equidigital number, since it uses as much as digits as its factorization.
1124242214023 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6144, while the sum is 28.
Adding to 1124242214023 its reverse (3204122424211), we get a palindrome (4328364638234).
The spelling of 1124242214023 in words is "one trillion, one hundred twenty-four billion, two hundred forty-two million, two hundred fourteen thousand, twenty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.070 sec. • engine limits •