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11243300041427 is a prime number
BaseRepresentation
bin1010001110011100100011…
…1001111011001011010011
31110210211220220121101002212
42203213020321323023103
52433202234302311202
635525033431502335
72240205312335216
oct243471071731323
943724826541085
1011243300041427
113645290841113
12131703a5279ab
136373143c08cc
142ac27021177d
151476e61c5652
hexa39c8e7b2d3

11243300041427 has 2 divisors, whose sum is σ = 11243300041428. Its totient is φ = 11243300041426.

The previous prime is 11243300041411. The next prime is 11243300041429. The reversal of 11243300041427 is 72414000334211.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 11243300041427 - 24 = 11243300041411 is a prime.

Together with 11243300041429, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 11243300041393 and 11243300041402.

It is not a weakly prime, because it can be changed into another prime (11243300041429) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5621650020713 + 5621650020714.

It is an arithmetic number, because the mean of its divisors is an integer number (5621650020714).

Almost surely, 211243300041427 is an apocalyptic number.

11243300041427 is a deficient number, since it is larger than the sum of its proper divisors (1).

11243300041427 is an equidigital number, since it uses as much as digits as its factorization.

11243300041427 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 16128, while the sum is 32.

Adding to 11243300041427 its reverse (72414000334211), we get a palindrome (83657300375638).

The spelling of 11243300041427 in words is "eleven trillion, two hundred forty-three billion, three hundred million, forty-one thousand, four hundred twenty-seven".