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11243335153 = 40927489817
BaseRepresentation
bin10100111100010011…
…11010110111110001
31002000120022121022111
422132021322313301
5141011243211103
65055355405321
7545422525531
oct123611726761
932016277274
1011243335153
11484a62a126
122219453841
1310a247554b
147893334c1
1545c10886d
hex29e27adf1

11243335153 has 4 divisors (see below), whose sum is σ = 11270825380. Its totient is φ = 11215844928.

The previous prime is 11243335121. The next prime is 11243335183. The reversal of 11243335153 is 35153334211.

It is a happy number.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 10366701489 + 876633664 = 101817^2 + 29608^2 .

It is a cyclic number.

It is not a de Polignac number, because 11243335153 - 25 = 11243335121 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (11243335183) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13744500 + ... + 13745317.

It is an arithmetic number, because the mean of its divisors is an integer number (2817706345).

Almost surely, 211243335153 is an apocalyptic number.

It is an amenable number.

11243335153 is a deficient number, since it is larger than the sum of its proper divisors (27490227).

11243335153 is an equidigital number, since it uses as much as digits as its factorization.

11243335153 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 27490226.

The product of its digits is 16200, while the sum is 31.

Adding to 11243335153 its reverse (35153334211), we get a palindrome (46396669364).

The spelling of 11243335153 in words is "eleven billion, two hundred forty-three million, three hundred thirty-five thousand, one hundred fifty-three".

Divisors: 1 409 27489817 11243335153