Base | Representation |
---|---|
bin | 10100111100010100… |
… | …10011010011100011 |
3 | 1002000120111200121020 |
4 | 22132022103103203 |
5 | 141011304411420 |
6 | 5055401500523 |
7 | 545423423364 |
oct | 123612232343 |
9 | 32016450536 |
10 | 11243435235 |
11 | 484a69833a |
12 | 22194a1743 |
13 | 10a24abc76 |
14 | 78935bb6b |
15 | 45c128340 |
hex | 29e2934e3 |
11243435235 has 16 divisors (see below), whose sum is σ = 18217213440. Its totient is φ = 5920593120.
The previous prime is 11243435201. The next prime is 11243435249. The reversal of 11243435235 is 53253434211.
11243435235 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 11243435235 - 227 = 11109217507 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 11243435196 and 11243435205.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 4742881 + ... + 4745250.
It is an arithmetic number, because the mean of its divisors is an integer number (1138575840).
Almost surely, 211243435235 is an apocalyptic number.
11243435235 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
11243435235 is a deficient number, since it is larger than the sum of its proper divisors (6973778205).
11243435235 is an equidigital number, since it uses as much as digits as its factorization.
11243435235 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 9488218.
The product of its digits is 43200, while the sum is 33.
Adding to 11243435235 its reverse (53253434211), we get a palindrome (64496869446).
The spelling of 11243435235 in words is "eleven billion, two hundred forty-three million, four hundred thirty-five thousand, two hundred thirty-five".
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