Base | Representation |
---|---|
bin | 10100111100011001… |
… | …00101100110100111 |
3 | 1002000121122010121011 |
4 | 22132030211212213 |
5 | 141011433100341 |
6 | 5055422403051 |
7 | 545431500415 |
oct | 123614454647 |
9 | 32017563534 |
10 | 11244034471 |
11 | 484aa6757a |
12 | 2219730487 |
13 | 10a265b947 |
14 | 7894762b5 |
15 | 45c1e5b81 |
hex | 29e3259a7 |
11244034471 has 2 divisors, whose sum is σ = 11244034472. Its totient is φ = 11244034470.
The previous prime is 11244034409. The next prime is 11244034507. The reversal of 11244034471 is 17443044211.
It is a happy number.
It is a strong prime.
It is an emirp because it is prime and its reverse (17443044211) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11244034471 - 229 = 10707163559 is a prime.
It is a super-3 number, since 3×112440344713 (a number of 31 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11244034271) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5622017235 + 5622017236.
It is an arithmetic number, because the mean of its divisors is an integer number (5622017236).
Almost surely, 211244034471 is an apocalyptic number.
11244034471 is a deficient number, since it is larger than the sum of its proper divisors (1).
11244034471 is an equidigital number, since it uses as much as digits as its factorization.
11244034471 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 10752, while the sum is 31.
Adding to 11244034471 its reverse (17443044211), we get a palindrome (28687078682).
The spelling of 11244034471 in words is "eleven billion, two hundred forty-four million, thirty-four thousand, four hundred seventy-one".
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