Base | Representation |
---|---|
bin | 10000010111001101011… |
… | …001001101001101001111 |
3 | 10222111100121221100102001 |
4 | 100113031121031031033 |
5 | 121410314143314411 |
6 | 2220320200413131 |
7 | 144144324466006 |
oct | 20271531151517 |
9 | 3874317840361 |
10 | 1124432401231 |
11 | 3a396185a727 |
12 | 161b0a1771a7 |
13 | 8205884bb19 |
14 | 3c5cc2ddc3d |
15 | 1e3b0905dc1 |
hex | 105cd64d34f |
1124432401231 has 2 divisors, whose sum is σ = 1124432401232. Its totient is φ = 1124432401230.
The previous prime is 1124432401223. The next prime is 1124432401277. The reversal of 1124432401231 is 1321042344211.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1124432401231 - 23 = 1124432401223 is a prime.
It is a super-2 number, since 2×11244324012312 (a number of 25 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 1124432401231.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1124432401931) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 562216200615 + 562216200616.
It is an arithmetic number, because the mean of its divisors is an integer number (562216200616).
Almost surely, 21124432401231 is an apocalyptic number.
1124432401231 is a deficient number, since it is larger than the sum of its proper divisors (1).
1124432401231 is an equidigital number, since it uses as much as digits as its factorization.
1124432401231 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 4608, while the sum is 28.
Adding to 1124432401231 its reverse (1321042344211), we get a palindrome (2445474745442).
The spelling of 1124432401231 in words is "one trillion, one hundred twenty-four billion, four hundred thirty-two million, four hundred one thousand, two hundred thirty-one".
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