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112444239953 is a prime number
BaseRepresentation
bin110100010111000110…
…0101111000001010001
3101202020102200020020202
41220232030233001101
53320241211134303
6123353422144545
711060321161313
oct1505614570121
9352212606222
10112444239953
1143761929831
1219961422155
13a7aca05236
145629a7b7b3
152dd19abc88
hex1a2e32f051

112444239953 has 2 divisors, whose sum is σ = 112444239954. Its totient is φ = 112444239952.

The previous prime is 112444239923. The next prime is 112444240009. The reversal of 112444239953 is 359932444211.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 111494552464 + 949687489 = 333908^2 + 30817^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-112444239953 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 112444239898 and 112444239907.

It is not a weakly prime, because it can be changed into another prime (112444239923) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56222119976 + 56222119977.

It is an arithmetic number, because the mean of its divisors is an integer number (56222119977).

Almost surely, 2112444239953 is an apocalyptic number.

It is an amenable number.

112444239953 is a deficient number, since it is larger than the sum of its proper divisors (1).

112444239953 is an equidigital number, since it uses as much as digits as its factorization.

112444239953 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 933120, while the sum is 47.

The spelling of 112444239953 in words is "one hundred twelve billion, four hundred forty-four million, two hundred thirty-nine thousand, nine hundred fifty-three".