Base | Representation |
---|---|
bin | 10100111100100111… |
… | …11001100101000100 |
3 | 1002000202020111222211 |
4 | 22132103321211010 |
5 | 141012430420200 |
6 | 5055531433204 |
7 | 545454003013 |
oct | 123623714504 |
9 | 32022214884 |
10 | 11245951300 |
11 | 4851056731 |
12 | 221a2b5804 |
13 | 10a2b8026c |
14 | 789814a7a |
15 | 45c473aba |
hex | 29e4f9944 |
11245951300 has 18 divisors (see below), whose sum is σ = 24403714538. Its totient is φ = 4498380480.
The previous prime is 11245951289. The next prime is 11245951319. The reversal of 11245951300 is 315954211.
11245951300 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It can be written as a sum of positive squares in 3 ways, for example, as 1807440196 + 9438511104 = 42514^2 + 97152^2 .
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 56229657 + ... + 56229856.
Almost surely, 211245951300 is an apocalyptic number.
11245951300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
11245951300 is an abundant number, since it is smaller than the sum of its proper divisors (13157763238).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
11245951300 is a wasteful number, since it uses less digits than its factorization.
11245951300 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 112459527 (or 112459520 counting only the distinct ones).
The product of its (nonzero) digits is 5400, while the sum is 31.
The spelling of 11245951300 in words is "eleven billion, two hundred forty-five million, nine hundred fifty-one thousand, three hundred".
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