Base | Representation |
---|---|
bin | 1010001110110101100110… |
… | …0001100010101110101111 |
3 | 1110211111021022212100222220 |
4 | 2203231121201202232233 |
5 | 2433310020424012310 |
6 | 35532104412010423 |
7 | 2240534005242411 |
oct | 243553141425657 |
9 | 43744238770886 |
10 | 11250021313455 |
11 | 364811a820291 |
12 | 13183b5460a13 |
13 | 637b45a36152 |
14 | 2ac70ab349b1 |
15 | 14798b2d3670 |
hex | a3b59862baf |
11250021313455 has 32 divisors (see below), whose sum is σ = 19120940745984. Its totient is φ = 5628675119616.
The previous prime is 11250021313439. The next prime is 11250021313513. The reversal of 11250021313455 is 55431312005211.
It is not a de Polignac number, because 11250021313455 - 24 = 11250021313439 is a prime.
It is a super-3 number, since 3×112500213134553 (a number of 40 digits) contains 333 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 71774697 + ... + 71931266.
It is an arithmetic number, because the mean of its divisors is an integer number (597529398312).
Almost surely, 211250021313455 is an apocalyptic number.
11250021313455 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
11250021313455 is a deficient number, since it is larger than the sum of its proper divisors (7870919432529).
11250021313455 is a wasteful number, since it uses less digits than its factorization.
11250021313455 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 143706295.
The product of its (nonzero) digits is 18000, while the sum is 33.
Adding to 11250021313455 its reverse (55431312005211), we get a palindrome (66681333318666).
The spelling of 11250021313455 in words is "eleven trillion, two hundred fifty billion, twenty-one million, three hundred thirteen thousand, four hundred fifty-five".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.082 sec. • engine limits •