Base | Representation |
---|---|
bin | 110100011000110111… |
… | …0000101010000001111 |
3 | 101202101112211110211001 |
4 | 1220301232011100033 |
5 | 3320401322012143 |
6 | 123403332241131 |
7 | 11061636246214 |
oct | 1506156052017 |
9 | 352345743731 |
10 | 112503313423 |
11 | 43792207586 |
12 | 199791701a7 |
13 | a7bc019557 |
14 | 5633857b0b |
15 | 2dd6c7a14d |
hex | 1a31b8540f |
112503313423 has 2 divisors, whose sum is σ = 112503313424. Its totient is φ = 112503313422.
The previous prime is 112503313387. The next prime is 112503313427. The reversal of 112503313423 is 324313305211.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-112503313423 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 112503313391 and 112503313400.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (112503313427) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56251656711 + 56251656712.
It is an arithmetic number, because the mean of its divisors is an integer number (56251656712).
Almost surely, 2112503313423 is an apocalyptic number.
112503313423 is a deficient number, since it is larger than the sum of its proper divisors (1).
112503313423 is an equidigital number, since it uses as much as digits as its factorization.
112503313423 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6480, while the sum is 28.
Adding to 112503313423 its reverse (324313305211), we get a palindrome (436816618634).
The spelling of 112503313423 in words is "one hundred twelve billion, five hundred three million, three hundred thirteen thousand, four hundred twenty-three".
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