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1125105433 is a prime number
BaseRepresentation
bin100001100001111…
…1011111100011001
32220102002021111121
41003003323330121
54301011333213
6303350525241
736611144524
oct10303737431
92812067447
101125105433
11528102401
12274966821
1314c130b7a
14a95d5bbb
1568b9488d
hex430fbf19

1125105433 has 2 divisors, whose sum is σ = 1125105434. Its totient is φ = 1125105432.

The previous prime is 1125105427. The next prime is 1125105437. The reversal of 1125105433 is 3345015211.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1101708864 + 23396569 = 33192^2 + 4837^2 .

It is a cyclic number.

It is not a de Polignac number, because 1125105433 - 29 = 1125104921 is a prime.

It is a super-2 number, since 2×11251054332 = 2531724470732234978, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1125105398 and 1125105407.

It is not a weakly prime, because it can be changed into another prime (1125105437) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 562552716 + 562552717.

It is an arithmetic number, because the mean of its divisors is an integer number (562552717).

Almost surely, 21125105433 is an apocalyptic number.

It is an amenable number.

1125105433 is a deficient number, since it is larger than the sum of its proper divisors (1).

1125105433 is an equidigital number, since it uses as much as digits as its factorization.

1125105433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1800, while the sum is 25.

The square root of 1125105433 is about 33542.5913280414. The cubic root of 1125105433 is about 1040.0744008040.

The spelling of 1125105433 in words is "one billion, one hundred twenty-five million, one hundred five thousand, four hundred thirty-three".