Base | Representation |
---|---|
bin | 1010001110111001101010… |
… | …0110011101100100111111 |
3 | 1110211121002102021222220112 |
4 | 2203232122212131210333 |
5 | 2433314234424401421 |
6 | 35532405013140235 |
7 | 2240603033411132 |
oct | 243563246354477 |
9 | 43747072258815 |
10 | 11251113122111 |
11 | 3648630050295 |
12 | 131865b02a67b |
13 | 637c8aca9585 |
14 | 2ac7b1b40219 |
15 | 147a0209c45b |
hex | a3b9a99d93f |
11251113122111 has 2 divisors, whose sum is σ = 11251113122112. Its totient is φ = 11251113122110.
The previous prime is 11251113122107. The next prime is 11251113122231. The reversal of 11251113122111 is 11122131115211.
It is a m-pointer prime, because the next prime (11251113122231) can be obtained adding 11251113122111 to its product of digits (120).
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11251113122111 - 22 = 11251113122107 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11251113122311) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5625556561055 + 5625556561056.
It is an arithmetic number, because the mean of its divisors is an integer number (5625556561056).
Almost surely, 211251113122111 is an apocalyptic number.
11251113122111 is a deficient number, since it is larger than the sum of its proper divisors (1).
11251113122111 is an equidigital number, since it uses as much as digits as its factorization.
11251113122111 is an evil number, because the sum of its binary digits is even.
The product of its digits is 120, while the sum is 23.
Adding to 11251113122111 its reverse (11122131115211), we get a palindrome (22373244237322).
The spelling of 11251113122111 in words is "eleven trillion, two hundred fifty-one billion, one hundred thirteen million, one hundred twenty-two thousand, one hundred eleven".
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