Base | Representation |
---|---|
bin | 10000011000000001111… |
… | …001101001010001000100 |
3 | 10222120122000112122210021 |
4 | 100120001321221101010 |
5 | 121414120202220004 |
6 | 2220543425504524 |
7 | 144205212253216 |
oct | 20300171512104 |
9 | 3876560478707 |
10 | 1125313320004 |
11 | 3a4274039a75 |
12 | 1621151a2144 |
13 | 821691c4333 |
14 | 3c6732d05b6 |
15 | 1e412e13d54 |
hex | 10601e69444 |
1125313320004 has 24 divisors (see below), whose sum is σ = 1972502325248. Its totient is φ = 561741972480.
The previous prime is 1125313319989. The next prime is 1125313320041. The reversal of 1125313320004 is 4000233135211.
It is a happy number.
It is a super-3 number, since 3×11253133200043 (a number of 37 digits) contains 333 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 6028189 + ... + 6212059.
Almost surely, 21125313320004 is an apocalyptic number.
It is an amenable number.
1125313320004 is a deficient number, since it is larger than the sum of its proper divisors (847189005244).
1125313320004 is a wasteful number, since it uses less digits than its factorization.
1125313320004 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 186355 (or 186353 counting only the distinct ones).
The product of its (nonzero) digits is 2160, while the sum is 25.
Adding to 1125313320004 its reverse (4000233135211), we get a palindrome (5125546455215).
The spelling of 1125313320004 in words is "one trillion, one hundred twenty-five billion, three hundred thirteen million, three hundred twenty thousand, four".
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