Base | Representation |
---|---|
bin | 110100011001101101… |
… | …0010001100100101111 |
3 | 101202110112012102012002 |
4 | 1220303122101210233 |
5 | 3320431102103224 |
6 | 123410224202515 |
7 | 11062432313261 |
oct | 1506332214457 |
9 | 352415172162 |
10 | 112531675439 |
11 | 437a7219367 |
12 | 1998676943b |
13 | a7c4b69b01 |
14 | 563751bb31 |
15 | 2dd94cd9ae |
hex | 1a3369192f |
112531675439 has 2 divisors, whose sum is σ = 112531675440. Its totient is φ = 112531675438.
The previous prime is 112531675409. The next prime is 112531675441. The reversal of 112531675439 is 934576135211.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-112531675439 is a prime.
Together with 112531675441, it forms a pair of twin primes.
It is a Chen prime.
It is a junction number, because it is equal to n+sod(n) for n = 112531675393 and 112531675402.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (112531675409) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56265837719 + 56265837720.
It is an arithmetic number, because the mean of its divisors is an integer number (56265837720).
Almost surely, 2112531675439 is an apocalyptic number.
112531675439 is a deficient number, since it is larger than the sum of its proper divisors (1).
112531675439 is an equidigital number, since it uses as much as digits as its factorization.
112531675439 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 680400, while the sum is 47.
The spelling of 112531675439 in words is "one hundred twelve billion, five hundred thirty-one million, six hundred seventy-five thousand, four hundred thirty-nine".
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