Base | Representation |
---|---|
bin | 110100011001110111… |
… | …1100010110110110101 |
3 | 101202110220200200202201 |
4 | 1220303233202312311 |
5 | 3320434014020003 |
6 | 123410543504501 |
7 | 11062530565300 |
oct | 1506357426665 |
9 | 352426620681 |
10 | 112537251253 |
11 | 437aa387579 |
12 | 199885b8131 |
13 | a7c606c9cb |
14 | 563816db37 |
15 | 2dd9c30b1d |
hex | 1a33be2db5 |
112537251253 has 12 divisors (see below), whose sum is σ = 138611309292. Its totient is φ = 90786353280.
The previous prime is 112537251187. The next prime is 112537251271. The reversal of 112537251253 is 352152735211.
It can be written as a sum of positive squares in 2 ways, for example, as 98494290244 + 14042961009 = 313838^2 + 118503^2 .
It is not a de Polignac number, because 112537251253 - 29 = 112537250741 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (112537257253) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 67548538 + ... + 67550203.
It is an arithmetic number, because the mean of its divisors is an integer number (11550942441).
Almost surely, 2112537251253 is an apocalyptic number.
It is an amenable number.
112537251253 is a deficient number, since it is larger than the sum of its proper divisors (26074058039).
112537251253 is a wasteful number, since it uses less digits than its factorization.
112537251253 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 135098772 (or 135098765 counting only the distinct ones).
The product of its digits is 63000, while the sum is 37.
Adding to 112537251253 its reverse (352152735211), we get a palindrome (464689986464).
The spelling of 112537251253 in words is "one hundred twelve billion, five hundred thirty-seven million, two hundred fifty-one thousand, two hundred fifty-three".
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