Base | Representation |
---|---|
bin | 1101011010100… |
… | …11101010001101 |
3 | 21211202122021022 |
4 | 12231103222031 |
5 | 212302242201 |
6 | 15100043525 |
7 | 2534401556 |
oct | 655235215 |
9 | 254678238 |
10 | 112540301 |
11 | 58587215 |
12 | 318335a5 |
13 | 1a4146c3 |
14 | 10d3732d |
15 | 9d3041b |
hex | 6b53a8d |
112540301 has 2 divisors, whose sum is σ = 112540302. Its totient is φ = 112540300.
The previous prime is 112540277. The next prime is 112540313. The reversal of 112540301 is 103045211.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 103510276 + 9030025 = 10174^2 + 3005^2 .
It is a cyclic number.
It is not a de Polignac number, because 112540301 - 26 = 112540237 is a prime.
It is a Chen prime.
It is a self number, because there is not a number n which added to its sum of digits gives 112540301.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (112540321) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56270150 + 56270151.
It is an arithmetic number, because the mean of its divisors is an integer number (56270151).
Almost surely, 2112540301 is an apocalyptic number.
It is an amenable number.
112540301 is a deficient number, since it is larger than the sum of its proper divisors (1).
112540301 is an equidigital number, since it uses as much as digits as its factorization.
112540301 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 120, while the sum is 17.
The square root of 112540301 is about 10608.5013550454. The cubic root of 112540301 is about 482.8023301433.
Adding to 112540301 its reverse (103045211), we get a palindrome (215585512).
The spelling of 112540301 in words is "one hundred twelve million, five hundred forty thousand, three hundred one".
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