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1125441368981 is a prime number
BaseRepresentation
bin10000011000001001100…
…010000111001110010101
310222120221221111012221222
4100120021202013032111
5121414400442301411
62221004242220125
7144211325536646
oct20301142071625
93876857435858
101125441368981
113a432a349076
12162150054645
13821898a8a67
143c6863036cd
151e41e2a94db
hex10609887395

1125441368981 has 2 divisors, whose sum is σ = 1125441368982. Its totient is φ = 1125441368980.

The previous prime is 1125441368963. The next prime is 1125441369011. The reversal of 1125441368981 is 1898631445211.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1099910122756 + 25531246225 = 1048766^2 + 159785^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1125441368981 is a prime.

It is a super-2 number, since 2×11254413689812 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1125441361981) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 562720684490 + 562720684491.

It is an arithmetic number, because the mean of its divisors is an integer number (562720684491).

Almost surely, 21125441368981 is an apocalyptic number.

It is an amenable number.

1125441368981 is a deficient number, since it is larger than the sum of its proper divisors (1).

1125441368981 is an equidigital number, since it uses as much as digits as its factorization.

1125441368981 is an evil number, because the sum of its binary digits is even.

The product of its digits is 1658880, while the sum is 53.

The spelling of 1125441368981 in words is "one trillion, one hundred twenty-five billion, four hundred forty-one million, three hundred sixty-eight thousand, nine hundred eighty-one".