Base | Representation |
---|---|
bin | 10000011000001110011… |
… | …001100011111101001111 |
3 | 10222121011122010012010101 |
4 | 100120032121203331033 |
5 | 121420032342412310 |
6 | 2221020320151531 |
7 | 144213336522331 |
oct | 20301631437517 |
9 | 3877148105111 |
10 | 1125523013455 |
11 | 3a4371442845 |
12 | 1621734685a7 |
13 | 821a07937b9 |
14 | 3c6930b7451 |
15 | 1e42653543a |
hex | 1060e663f4f |
1125523013455 has 64 divisors (see below), whose sum is σ = 1429689139200. Its totient is φ = 849358236160.
The previous prime is 1125523013431. The next prime is 1125523013477. The reversal of 1125523013455 is 5543103255211.
It is not a de Polignac number, because 1125523013455 - 223 = 1125514624847 is a prime.
It is a super-2 number, since 2×11255230134552 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 1412199117 + ... + 1412199913.
It is an arithmetic number, because the mean of its divisors is an integer number (22338892800).
Almost surely, 21125523013455 is an apocalyptic number.
1125523013455 is a deficient number, since it is larger than the sum of its proper divisors (304166125745).
1125523013455 is a wasteful number, since it uses less digits than its factorization.
1125523013455 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1704.
The product of its (nonzero) digits is 90000, while the sum is 37.
Adding to 1125523013455 its reverse (5543103255211), we get a palindrome (6668626268666).
The spelling of 1125523013455 in words is "one trillion, one hundred twenty-five billion, five hundred twenty-three million, thirteen thousand, four hundred fifty-five".
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