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112753000715 = 522550600143
BaseRepresentation
bin110100100000010011…
…0100100000100001011
3101210000221122220101112
41221000212210010023
53321404232010330
6123444212040535
711101060456415
oct1510046440413
9353027586345
10112753000715
1143900147313
1219a2890314b
13a82b97c804
145658a919b5
152dedb4b795
hex1a409a410b

112753000715 has 4 divisors (see below), whose sum is σ = 135303600864. Its totient is φ = 90202400568.

The previous prime is 112753000637. The next prime is 112753000733. The reversal of 112753000715 is 517000357211.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 112753000715 - 236 = 44033523979 is a prime.

It is a super-2 number, since 2×1127530007152 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 11275300067 + ... + 11275300076.

It is an arithmetic number, because the mean of its divisors is an integer number (33825900216).

Almost surely, 2112753000715 is an apocalyptic number.

112753000715 is a deficient number, since it is larger than the sum of its proper divisors (22550600149).

112753000715 is an equidigital number, since it uses as much as digits as its factorization.

112753000715 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 22550600148.

The product of its (nonzero) digits is 7350, while the sum is 32.

Adding to 112753000715 its reverse (517000357211), we get a palindrome (629753357926).

The spelling of 112753000715 in words is "one hundred twelve billion, seven hundred fifty-three million, seven hundred fifteen", and thus it is an aban number.

Divisors: 1 5 22550600143 112753000715