11300000053 has 2 divisors, whose sum is σ = 11300000054. Its totient is φ = 11300000052.

The previous prime is 11300000009. The next prime is 11300000071. The reversal of 11300000053 is 35000000311.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 8467312324 + 2832687729 = 92018^2 + 53223^2 .

It is an emirp because it is prime and its reverse (35000000311) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11300000053 - 2¹⁷ = 11299868981 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11299999979 and 11300000042.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11300000653) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5650000026 + 5650000027.

It is an arithmetic number, because the mean of its divisors is an integer number (5650000027).

Almost surely, 2^11300000053 is an apocalyptic number.

It is an amenable number.

11300000053 is a deficient number, since it is larger than the sum of its proper divisors (1).

11300000053 is an equidigital number, since it uses as much as digits as its factorization.

11300000053 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 45, while the sum is 13.

Adding to 11300000053 its reverse (35000000311), we get a palindrome (46300000364).

The spelling of 11300000053 in words is "eleven billion, three hundred million, fifty-three", and thus it is an aban number.