Base | Representation |
---|---|
bin | 10000011100011001010… |
… | …011101110101010100000 |
3 | 11000000201201020112101101 |
4 | 100130121103232222200 |
5 | 122003220224013440 |
6 | 2223040523044144 |
7 | 144432323013055 |
oct | 20343123565240 |
9 | 4000651215341 |
10 | 1130001001120 |
11 | 3a625a1191a2 |
12 | 163003070654 |
13 | 82735430c44 |
14 | 3c999ad302c |
15 | 1e5d972669a |
hex | 107194eeaa0 |
1130001001120 has 24 divisors (see below), whose sum is σ = 2669627365524. Its totient is φ = 452000400384.
The previous prime is 1130001001099. The next prime is 1130001001183. The reversal of 1130001001120 is 211001000311.
It can be written as a sum of positive squares in 2 ways, for example, as 1073552943376 + 56448057744 = 1036124^2 + 237588^2 .
It is a Harshad number since it is a multiple of its sum of digits (10).
It is a junction number, because it is equal to n+sod(n) for n = 1130001001097 and 1130001001106.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3531252969 + ... + 3531253288.
Almost surely, 21130001001120 is an apocalyptic number.
1130001001120 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
1130001001120 is an abundant number, since it is smaller than the sum of its proper divisors (1539626364404).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1130001001120 is an equidigital number, since it uses as much as digits as its factorization.
1130001001120 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7062506272 (or 7062506264 counting only the distinct ones).
The product of its (nonzero) digits is 6, while the sum is 10.
Adding to 1130001001120 its reverse (211001000311), we get a palindrome (1341002001431).
The spelling of 1130001001120 in words is "one trillion, one hundred thirty billion, one million, one thousand, one hundred twenty".
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