Base | Representation |
---|---|
bin | 10101000011000101… |
… | …00000011101011111 |
3 | 1002011112011011210221 |
4 | 22201202200131133 |
5 | 141120312042343 |
6 | 5105144342211 |
7 | 550012240411 |
oct | 124142403537 |
9 | 32145134727 |
10 | 11300112223 |
11 | 4879689624 |
12 | 2234474967 |
13 | 10b116454a |
14 | 792ab29b1 |
15 | 4620c15ed |
hex | 2a18a075f |
11300112223 has 2 divisors, whose sum is σ = 11300112224. Its totient is φ = 11300112222.
The previous prime is 11300112203. The next prime is 11300112251. The reversal of 11300112223 is 32221100311.
It is a weak prime.
It is an emirp because it is prime and its reverse (32221100311) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11300112223 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 11300112197 and 11300112206.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11300112203) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5650056111 + 5650056112.
It is an arithmetic number, because the mean of its divisors is an integer number (5650056112).
Almost surely, 211300112223 is an apocalyptic number.
11300112223 is a deficient number, since it is larger than the sum of its proper divisors (1).
11300112223 is an equidigital number, since it uses as much as digits as its factorization.
11300112223 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 72, while the sum is 16.
Adding to 11300112223 its reverse (32221100311), we get a palindrome (43521212534).
The spelling of 11300112223 in words is "eleven billion, three hundred million, one hundred twelve thousand, two hundred twenty-three".
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