Base | Representation |
---|---|
bin | 10000011100011001111… |
… | …101101100101011101011 |
3 | 11000000202110221111012022 |
4 | 100130121331230223223 |
5 | 122003231033044201 |
6 | 2223041554535055 |
7 | 144432515354501 |
oct | 20343175545353 |
9 | 4000673844168 |
10 | 1130012003051 |
11 | 3a62653530a8 |
12 | 16300689748b |
13 | 827377b3869 |
14 | 3c99b358671 |
15 | 1e5da69b41b |
hex | 10719f6caeb |
1130012003051 has 2 divisors, whose sum is σ = 1130012003052. Its totient is φ = 1130012003050.
The previous prime is 1130012003023. The next prime is 1130012003137. The reversal of 1130012003051 is 1503002100311.
It is a weak prime.
It is an emirp because it is prime and its reverse (1503002100311) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1130012003051 is a prime.
It is not a weakly prime, because it can be changed into another prime (1130012003951) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 565006001525 + 565006001526.
It is an arithmetic number, because the mean of its divisors is an integer number (565006001526).
Almost surely, 21130012003051 is an apocalyptic number.
1130012003051 is a deficient number, since it is larger than the sum of its proper divisors (1).
1130012003051 is an equidigital number, since it uses as much as digits as its factorization.
1130012003051 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 90, while the sum is 17.
Adding to 1130012003051 its reverse (1503002100311), we get a palindrome (2633014103362).
The spelling of 1130012003051 in words is "one trillion, one hundred thirty billion, twelve million, three thousand, fifty-one".
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