Base | Representation |
---|---|
bin | 11001101100011001011011… |
… | …110100101100111001100101 |
3 | 112211002220020201222100011212 |
4 | 121230121123310230321211 |
5 | 104302411330301143223 |
6 | 1040200243434441205 |
7 | 32542064061363323 |
oct | 3154313364547145 |
9 | 484086221870155 |
10 | 113002130099813 |
11 | 33007a30533439 |
12 | 108106a0893205 |
13 | 4b090941ca746 |
14 | 1dc9491abad13 |
15 | d0e6a0e67278 |
hex | 66c65bd2ce65 |
113002130099813 has 2 divisors, whose sum is σ = 113002130099814. Its totient is φ = 113002130099812.
The previous prime is 113002130099777. The next prime is 113002130100017. The reversal of 113002130099813 is 318990031200311.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 79093950936484 + 33908179163329 = 8893478^2 + 5823073^2 .
It is a cyclic number.
It is not a de Polignac number, because 113002130099813 - 214 = 113002130083429 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (113002130099413) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56501065049906 + 56501065049907.
It is an arithmetic number, because the mean of its divisors is an integer number (56501065049907).
Almost surely, 2113002130099813 is an apocalyptic number.
It is an amenable number.
113002130099813 is a deficient number, since it is larger than the sum of its proper divisors (1).
113002130099813 is an equidigital number, since it uses as much as digits as its factorization.
113002130099813 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 34992, while the sum is 41.
The spelling of 113002130099813 in words is "one hundred thirteen trillion, two billion, one hundred thirty million, ninety-nine thousand, eight hundred thirteen".
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