Base | Representation |
---|---|
bin | 11001101100011001011011… |
… | …110100101100111100110001 |
3 | 112211002220020201222100110102 |
4 | 121230121123310230330301 |
5 | 104302411330301200032 |
6 | 1040200243434442145 |
7 | 32542064061364034 |
oct | 3154313364547461 |
9 | 484086221870412 |
10 | 113002130100017 |
11 | 33007a30533604 |
12 | 108106a0893355 |
13 | 4b090941ca872 |
14 | 1dc9491abb01b |
15 | d0e6a0e67362 |
hex | 66c65bd2cf31 |
113002130100017 has 2 divisors, whose sum is σ = 113002130100018. Its totient is φ = 113002130100016.
The previous prime is 113002130099813. The next prime is 113002130100019. The reversal of 113002130100017 is 710001031200311.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 75168362460961 + 37833767639056 = 8669969^2 + 6150916^2 .
It is a cyclic number.
It is not a de Polignac number, because 113002130100017 - 216 = 113002130034481 is a prime.
Together with 113002130100019, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (113002130100019) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56501065050008 + 56501065050009.
It is an arithmetic number, because the mean of its divisors is an integer number (56501065050009).
Almost surely, 2113002130100017 is an apocalyptic number.
It is an amenable number.
113002130100017 is a deficient number, since it is larger than the sum of its proper divisors (1).
113002130100017 is an equidigital number, since it uses as much as digits as its factorization.
113002130100017 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 126, while the sum is 20.
Adding to 113002130100017 its reverse (710001031200311), we get a palindrome (823003161300328).
The spelling of 113002130100017 in words is "one hundred thirteen trillion, two billion, one hundred thirty million, one hundred thousand, seventeen".
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