Base | Representation |
---|---|
bin | 110100100111101110… |
… | …1010011000101101010 |
3 | 101210200022122001212022 |
4 | 1221033131103011222 |
5 | 3322412032330442 |
6 | 123525033544442 |
7 | 11110205051645 |
oct | 1511735230552 |
9 | 353608561768 |
10 | 113002230122 |
11 | 43a188a4031 |
12 | 19a98275122 |
13 | a86b4b2532 |
14 | 567dc0aa5c |
15 | 2e1597c3d2 |
hex | 1a4f75316a |
113002230122 has 4 divisors (see below), whose sum is σ = 169503345186. Its totient is φ = 56501115060.
The previous prime is 113002230109. The next prime is 113002230137. The reversal of 113002230122 is 221032200311.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 221032200311 = 13 ⋅17002476947.
It can be written as a sum of positive squares in only one way, i.e., 96353747281 + 16648482841 = 310409^2 + 129029^2 .
It is a self number, because there is not a number n which added to its sum of digits gives 113002230122.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 28250557529 + ... + 28250557532.
Almost surely, 2113002230122 is an apocalyptic number.
113002230122 is a deficient number, since it is larger than the sum of its proper divisors (56501115064).
113002230122 is an equidigital number, since it uses as much as digits as its factorization.
113002230122 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 56501115063.
The product of its (nonzero) digits is 144, while the sum is 17.
Adding to 113002230122 its reverse (221032200311), we get a palindrome (334034430433).
It can be divided in two parts, 11300 and 2230122, that added together give a palindrome (2241422).
The spelling of 113002230122 in words is "one hundred thirteen billion, two million, two hundred thirty thousand, one hundred twenty-two".
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