Base | Representation |
---|---|
bin | 10101000011000101… |
… | …11100000111111101 |
3 | 1002011112100221020121 |
4 | 22201202330013331 |
5 | 141120324204113 |
6 | 5105151014541 |
7 | 550013221642 |
oct | 124142740775 |
9 | 32145327217 |
10 | 11300225533 |
11 | 4879756773 |
12 | 223450a451 |
13 | 10b11a3cac |
14 | 792b01dc9 |
15 | 4620e4e8d |
hex | 2a18bc1fd |
11300225533 has 4 divisors (see below), whose sum is σ = 11964944700. Its totient is φ = 10635506368.
The previous prime is 11300225501. The next prime is 11300225551. The reversal of 11300225533 is 33552200311.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 4041526329 + 7258699204 = 63573^2 + 85198^2 .
It is a cyclic number.
It is not a de Polignac number, because 11300225533 - 25 = 11300225501 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 11300225498 and 11300225507.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11300205533) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 332359558 + ... + 332359591.
It is an arithmetic number, because the mean of its divisors is an integer number (2991236175).
Almost surely, 211300225533 is an apocalyptic number.
It is an amenable number.
11300225533 is a deficient number, since it is larger than the sum of its proper divisors (664719167).
11300225533 is an equidigital number, since it uses as much as digits as its factorization.
11300225533 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 664719166.
The product of its (nonzero) digits is 2700, while the sum is 25.
Adding to 11300225533 its reverse (33552200311), we get a palindrome (44852425844).
The spelling of 11300225533 in words is "eleven billion, three hundred million, two hundred twenty-five thousand, five hundred thirty-three".
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