Base | Representation |
---|---|
bin | 10101000011000110… |
… | …10011001101110010 |
3 | 1002011112112201222121 |
4 | 22201203103031302 |
5 | 141120340220424 |
6 | 5105153024454 |
7 | 550014064456 |
oct | 124143231562 |
9 | 32145481877 |
10 | 11300320114 |
11 | 4879810836 |
12 | 223455512a |
13 | 10b1208065 |
14 | 792b28666 |
15 | 462112ee4 |
hex | 2a18d3372 |
11300320114 has 4 divisors (see below), whose sum is σ = 16950480174. Its totient is φ = 5650160056.
The previous prime is 11300320103. The next prime is 11300320117. The reversal of 11300320114 is 41102300311.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 41102300311 = 89 ⋅461823599.
It can be written as a sum of positive squares in only one way, i.e., 11253602889 + 46717225 = 106083^2 + 6835^2 .
It is not an unprimeable number, because it can be changed into a prime (11300320117) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2825080027 + ... + 2825080030.
Almost surely, 211300320114 is an apocalyptic number.
11300320114 is a deficient number, since it is larger than the sum of its proper divisors (5650160060).
11300320114 is an equidigital number, since it uses as much as digits as its factorization.
11300320114 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5650160059.
The product of its (nonzero) digits is 72, while the sum is 16.
Adding to 11300320114 its reverse (41102300311), we get a palindrome (52402620425).
The spelling of 11300320114 in words is "eleven billion, three hundred million, three hundred twenty thousand, one hundred fourteen".
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