Base | Representation |
---|---|
bin | 10101000011000110… |
… | …10011001101100111 |
3 | 1002011112112201222012 |
4 | 22201203103031213 |
5 | 141120340220403 |
6 | 5105153024435 |
7 | 550014064442 |
oct | 124143231547 |
9 | 32145481865 |
10 | 11300320103 |
11 | 4879810826 |
12 | 223455511b |
13 | 10b1208057 |
14 | 792b28659 |
15 | 462112ed8 |
hex | 2a18d3367 |
11300320103 has 2 divisors, whose sum is σ = 11300320104. Its totient is φ = 11300320102.
The previous prime is 11300320099. The next prime is 11300320117. The reversal of 11300320103 is 30102300311.
11300320103 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is an a-pointer prime, because the next prime (11300320117) can be obtained adding 11300320103 to its sum of digits (14).
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11300320103 - 22 = 11300320099 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11300320123) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5650160051 + 5650160052.
It is an arithmetic number, because the mean of its divisors is an integer number (5650160052).
Almost surely, 211300320103 is an apocalyptic number.
11300320103 is a deficient number, since it is larger than the sum of its proper divisors (1).
11300320103 is an equidigital number, since it uses as much as digits as its factorization.
11300320103 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 54, while the sum is 14.
Adding to 11300320103 its reverse (30102300311), we get a palindrome (41402620414).
The spelling of 11300320103 in words is "eleven billion, three hundred million, three hundred twenty thousand, one hundred three".
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