Base | Representation |
---|---|
bin | 10000011100011011101… |
… | …110001110001010110111 |
3 | 11000000211112110002212121 |
4 | 100130123232032022313 |
5 | 122003311111002333 |
6 | 2223044531100411 |
7 | 144433324160440 |
oct | 20343356161267 |
9 | 4000745402777 |
10 | 1130041500343 |
11 | 3a627aa6a928 |
12 | 163014741707 |
13 | 82740940a92 |
14 | 3c9a12362c7 |
15 | 1e5dd07632d |
hex | 1071bb8e2b7 |
1130041500343 has 8 divisors (see below), whose sum is σ = 1291483802912. Its totient is φ = 968601148416.
The previous prime is 1130041500337. The next prime is 1130041500349. The reversal of 1130041500343 is 3430051400311.
It is an interprime number because it is at equal distance from previous prime (1130041500337) and next prime (1130041500349).
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 1130041500343 - 29 = 1130041499831 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1130041500349) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1097071 + ... + 1861087.
It is an arithmetic number, because the mean of its divisors is an integer number (161435475364).
Almost surely, 21130041500343 is an apocalyptic number.
1130041500343 is a deficient number, since it is larger than the sum of its proper divisors (161442302569).
1130041500343 is an equidigital number, since it uses as much as digits as its factorization.
1130041500343 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 975321.
The product of its (nonzero) digits is 2160, while the sum is 25.
Adding to 1130041500343 its reverse (3430051400311), we get a palindrome (4560092900654).
The spelling of 1130041500343 in words is "one trillion, one hundred thirty billion, forty-one million, five hundred thousand, three hundred forty-three".
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