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1130041500343 = 7211297764017
BaseRepresentation
bin10000011100011011101…
…110001110001010110111
311000000211112110002212121
4100130123232032022313
5122003311111002333
62223044531100411
7144433324160440
oct20343356161267
94000745402777
101130041500343
113a627aa6a928
12163014741707
1382740940a92
143c9a12362c7
151e5dd07632d
hex1071bb8e2b7

1130041500343 has 8 divisors (see below), whose sum is σ = 1291483802912. Its totient is φ = 968601148416.

The previous prime is 1130041500337. The next prime is 1130041500349. The reversal of 1130041500343 is 3430051400311.

It is an interprime number because it is at equal distance from previous prime (1130041500337) and next prime (1130041500349).

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 1130041500343 - 29 = 1130041499831 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1130041500349) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1097071 + ... + 1861087.

It is an arithmetic number, because the mean of its divisors is an integer number (161435475364).

Almost surely, 21130041500343 is an apocalyptic number.

1130041500343 is a deficient number, since it is larger than the sum of its proper divisors (161442302569).

1130041500343 is an equidigital number, since it uses as much as digits as its factorization.

1130041500343 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 975321.

The product of its (nonzero) digits is 2160, while the sum is 25.

Adding to 1130041500343 its reverse (3430051400311), we get a palindrome (4560092900654).

The spelling of 1130041500343 in words is "one trillion, one hundred thirty billion, forty-one million, five hundred thousand, three hundred forty-three".

Divisors: 1 7 211297 764017 1479079 5348119 161434500049 1130041500343