113007497143 has 4 divisors (see below), whose sum is σ = 117920866608. Its totient is φ = 108094127680.

The previous prime is 113007497117. The next prime is 113007497149. The reversal of 113007497143 is 341794700311.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-113007497143 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 113007497096 and 113007497105.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (113007497149) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2456684698 + ... + 2456684743.

It is an arithmetic number, because the mean of its divisors is an integer number (29480216652).

Almost surely, 2^113007497143 is an apocalyptic number.

113007497143 is a deficient number, since it is larger than the sum of its proper divisors (4913369465).

113007497143 is an equidigital number, since it uses as much as digits as its factorization.

113007497143 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4913369464.

The product of its (nonzero) digits is 63504, while the sum is 40.

The spelling of 113007497143 in words is "one hundred thirteen billion, seven million, four hundred ninety-seven thousand, one hundred forty-three".