113010131130000 has 400 divisors, whose sum is σ = 392925238675200. Its totient is φ = 27814265856000.

The previous prime is 113010131129993. The next prime is 113010131130133. The reversal of 113010131130000 is 31131010311.

It is a tau number, because it is divible by the number of its divisors (400).

It is a Harshad number since it is a multiple of its sum of digits (15).

It is an unprimeable number.

It is a polite number, since it can be written in 79 ways as a sum of consecutive naturals, for example, 4211596584 + ... + 4211623416.

It is an arithmetic number, because the mean of its divisors is an integer number (982313096688).

Almost surely, 2^{113010131130000} is an apocalyptic number.

113010131130000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 113010131130000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (196462619337600).

113010131130000 is an abundant number, since it is smaller than the sum of its proper divisors (279915107545200).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

113010131130000 is a wasteful number, since it uses less digits than its factorization.

113010131130000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 37676 (or 37655 counting only the distinct ones).

The product of its (nonzero) digits is 27, while the sum is 15.

Adding to 113010131130000 its reverse (31131010311), we get a palindrome (113041262140311).

The spelling of 113010131130000 in words is "one hundred thirteen trillion, ten billion, one hundred thirty-one million, one hundred thirty thousand".