Base | Representation |
---|---|
bin | 10101000011001100… |
… | …00001010010110111 |
3 | 1002011120212222002002 |
4 | 22201212001102313 |
5 | 141121031030033 |
6 | 5105220205515 |
7 | 550023124331 |
oct | 124146012267 |
9 | 32146788062 |
10 | 11301033143 |
11 | 487a158514 |
12 | 223483989b |
13 | 10b13c777a |
14 | 792c72451 |
15 | 4622043e8 |
hex | 2a19814b7 |
11301033143 has 4 divisors (see below), whose sum is σ = 11366357208. Its totient is φ = 11235709080.
The previous prime is 11301033137. The next prime is 11301033239. The reversal of 11301033143 is 34133010311.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 11301033143 - 28 = 11301032887 is a prime.
It is a super-3 number, since 3×113010331433 (a number of 31 digits) contains 333 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11301033343) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 32661773 + ... + 32662118.
It is an arithmetic number, because the mean of its divisors is an integer number (2841589302).
Almost surely, 211301033143 is an apocalyptic number.
11301033143 is a deficient number, since it is larger than the sum of its proper divisors (65324065).
11301033143 is an equidigital number, since it uses as much as digits as its factorization.
11301033143 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 65324064.
The product of its (nonzero) digits is 324, while the sum is 20.
Adding to 11301033143 its reverse (34133010311), we get a palindrome (45434043454).
The spelling of 11301033143 in words is "eleven billion, three hundred one million, thirty-three thousand, one hundred forty-three".
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