113010551 has 2 divisors, whose sum is σ = 113010552. Its totient is φ = 113010550.

The previous prime is 113010539. The next prime is 113010581. The reversal of 113010551 is 155010311.

It is a weak prime.

It is an emirp because it is prime and its reverse (155010311) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 113010551 - 2¹⁰ = 113009527 is a prime.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (113010581) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56505275 + 56505276.

It is an arithmetic number, because the mean of its divisors is an integer number (56505276).

Almost surely, 2^113010551 is an apocalyptic number.

113010551 is a deficient number, since it is larger than the sum of its proper divisors (1).

113010551 is an equidigital number, since it uses as much as digits as its factorization.

113010551 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 75, while the sum is 17.

The square root of 113010551 is about 10630.6420784447. The cubic root of 113010551 is about 483.4738593636.

Adding to 113010551 its reverse (155010311), we get a palindrome (268020862).

The spelling of 113010551 in words is "one hundred thirteen million, ten thousand, five hundred fifty-one".