Base | Representation |
---|---|
bin | 10101000011001100… |
… | …11001001110000111 |
3 | 1002011121001221111201 |
4 | 22201212121032013 |
5 | 141121042144033 |
6 | 5105222243331 |
7 | 550024013131 |
oct | 124146311607 |
9 | 32147057451 |
10 | 11301131143 |
11 | 487a215105 |
12 | 2234886547 |
13 | 10b1430263 |
14 | 792c9a051 |
15 | 46222347d |
hex | 2a1999387 |
11301131143 has 2 divisors, whose sum is σ = 11301131144. Its totient is φ = 11301131142.
The previous prime is 11301131111. The next prime is 11301131173. The reversal of 11301131143 is 34113110311.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11301131143 - 25 = 11301131111 is a prime.
It is a super-2 number, since 2×113011311432 (a number of 21 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 11301131143.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11301131173) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5650565571 + 5650565572.
It is an arithmetic number, because the mean of its divisors is an integer number (5650565572).
Almost surely, 211301131143 is an apocalyptic number.
11301131143 is a deficient number, since it is larger than the sum of its proper divisors (1).
11301131143 is an equidigital number, since it uses as much as digits as its factorization.
11301131143 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 108, while the sum is 19.
Adding to 11301131143 its reverse (34113110311), we get a palindrome (45414241454).
The spelling of 11301131143 in words is "eleven billion, three hundred one million, one hundred thirty-one thousand, one hundred forty-three".
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