11301133131997 has 2 divisors, whose sum is σ = 11301133131998. Its totient is φ = 11301133131996.

The previous prime is 11301133131971. The next prime is 11301133132067. The reversal of 11301133131997 is 79913133110311.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 5983962933796 + 5317170198201 = 2446214^2 + 2305899^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-11301133131997 is a prime.

It is a super-3 number, since 3×11301133131997³ (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11301133131917) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5650566565998 + 5650566565999.

It is an arithmetic number, because the mean of its divisors is an integer number (5650566565999).

Almost surely, 2^{11301133131997} is an apocalyptic number.

It is an amenable number.

11301133131997 is a deficient number, since it is larger than the sum of its proper divisors (1).

11301133131997 is an equidigital number, since it uses as much as digits as its factorization.

11301133131997 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 45927, while the sum is 43.

The spelling of 11301133131997 in words is "eleven trillion, three hundred one billion, one hundred thirty-three million, one hundred thirty-one thousand, nine hundred ninety-seven".