11301133132032 has 36 divisors (see below), whose sum is σ = 30077494952400. Its totient is φ = 3767044377088.

The previous prime is 11301133131997. The next prime is 11301133132067. The reversal of 11301133132032 is 23023133110311.

It is an interprime number because it is at equal distance from previous prime (11301133131997) and next prime (11301133132067).

It is a super-3 number, since 3×11301133132032³ (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Harshad number since it is a multiple of its sum of digits (24).

It is a junction number, because it is equal to n+sod(n) for n = 11301133131993 and 11301133132011.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7357507782 + ... + 7357509317.

It is an arithmetic number, because the mean of its divisors is an integer number (835485970900).

Almost surely, 2^{11301133132032} is an apocalyptic number.

11301133132032 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

11301133132032 is an abundant number, since it is smaller than the sum of its proper divisors (18776361820368).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

11301133132032 is an equidigital number, since it uses as much as digits as its factorization.

11301133132032 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 14715017118 (or 14715017104 counting only the distinct ones).

The product of its (nonzero) digits is 972, while the sum is 24.

Adding to 11301133132032 its reverse (23023133110311), we get a palindrome (34324266242343).

The spelling of 11301133132032 in words is "eleven trillion, three hundred one billion, one hundred thirty-three million, one hundred thirty-two thousand, thirty-two".