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113014115 = 522602823
BaseRepresentation
bin1101011110001…
…11010101100011
321212122201012222
412233013111203
5212412422430
615114141255
72541414134
oct657072543
9255581188
10113014115
11588801a5
1231a2182b
131a54c276
141101bc8b
159dc59e5
hex6bc7563

113014115 has 4 divisors (see below), whose sum is σ = 135616944. Its totient is φ = 90411288.

The previous prime is 113014103. The next prime is 113014117. The reversal of 113014115 is 511410311.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 113014115 - 210 = 113013091 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 113014093 and 113014102.

It is not an unprimeable number, because it can be changed into a prime (113014117) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 11301407 + ... + 11301416.

It is an arithmetic number, because the mean of its divisors is an integer number (33904236).

Almost surely, 2113014115 is an apocalyptic number.

113014115 is a deficient number, since it is larger than the sum of its proper divisors (22602829).

113014115 is an equidigital number, since it uses as much as digits as its factorization.

113014115 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 22602828.

The product of its (nonzero) digits is 60, while the sum is 17.

The square root of 113014115 is about 10630.8097057562. The cubic root of 113014115 is about 483.4789417289.

Adding to 113014115 its reverse (511410311), we get a palindrome (624424426).

The spelling of 113014115 in words is "one hundred thirteen million, fourteen thousand, one hundred fifteen".

Divisors: 1 5 22602823 113014115